You are given an array of integers, marks, denoting the marks scored by students in a class.
- The alternating elements marks0, marks2, marks4 and so on denote the marks of boys.
- Similarly, marks1, marks3, marks5 and so on denote the marks of girls.
The array name, marks, works as a pointer which stores the base address of that array. In other words, marks contains the address where marks0 is stored in the memory.
For example, let marks = [3,2,5] and marks stores 0x7fff9575c05f. Then, 0x7fff9575c05f is the memory address of marks0.
Complete the function, marks_summation(int* marks, char gender, int number_of_students) which returns the total sum of:
- marks of boys if gender = b
- marks of girls if gender = g
The locked code stub reads the elements of marks along with gender. Then, it calls the function marks_summation(marks, gender, number_of_students) to get the sum of alternate elements as explained above and then prints the sum.
Input Format
- The first line contains number_of_students, denoting the number of students in the class, hence the number of elements in marks.
- Each of the number_of_students subsequent lines contains marksi.
- The next line contains gender.
Constraints
- 1 <= number_of_students <= 103
- 1 <= marksi <= 103 (where 0<= i <= number_of_students )
- gender = g or b
Output Format
The output should contain the sum of all the aternate elements in marks as explained above.
Sample Input 0
3
3
2
5
b
Sample Output 0
8
Explanation 0
marks = [3, 2, 5] and gender = b.
So, marks0 + marks2 = 3 + 5 = 8.
Sample Input 1
5
1
2
3
4
5
g
Sample Output
6
Explanation 1
marks = [1, 2, 3, 4, 5] and gender = g
So, sum = marks1 + marks3 = 2+5 =8.
Sample Input 2
1
5
g
Sample Output 2
0
Explanation 2
marks = [5] and gender = g
Here, marks1 does not exist. So, sum = 0.
Students Marks Sum - HackerRank Solution
#include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h> //Complete the following function. int marks_summation(int * p, int number_of_students, char gender) { int s = 0, i = 0; if (gender == 'g') { i++; } for (; i < number_of_students; i = i + 2) { s += p[i]; } return s; } int main() { int number_of_students; char gender; int sum; scanf("%d", & number_of_students); int * marks = (int * ) malloc(number_of_students * sizeof(int)); for (int student = 0; student < number_of_students; student++) { scanf("%d", (marks + student)); } scanf(" %c", & gender); sum = marks_summation(marks, number_of_students, gender); printf("%d", sum); free(marks); return 0; }
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